Shell脚本基础循环、判断语句练习实例

商场购物车案例

#! /bin/bash

xie=200
ku=150
yi=100
huan=50
chi=120
num=0
for ((i=1;i<=5;i++))
do
echo 是否进入第"$i"家店?
read -p "输入(yes & no)" shu 
while [ $shu = "yes" ]
do
  echo 1.鞋子   ¥"$xie"
  echo 2.裤子   ¥"$ku"       
  echo 3.衣服   ¥"$yi"        
  echo 4.手环   ¥"$huan"     
  echo 5.小吃   ¥"$chi"      
 echo "您想购买哪件商品?"
 read bh
echo "是否继续购物?(yes & no)"
read shu
case $bh in
1)
 let num+=$xie
 echo 总价为"$num" &> /dev/null
;;

2)
 let num+=$ku
 echo 总价为"$num"&> /dev/null
;;

3)
 let num+=$yi
 echo 总价为"$num"&> /dev/null
;;

4)
 let num+=$huan
 echo 总价为"$num"&> /dev/null
;;

5)
 let num+=$chi
 echo 总价为"$num"&> /dev/null
;;

*)
 echo "您的选择有误,请检查输入"
esac
done
done
echo 您本次购买的总价为:$num

标签: echo, dev, Shell, null, 实例, let, num, 总价, 商场

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